y=(x+1)2(x^2+2x)

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Solution for y=(x+1)2(x^2+2x) equation: 


Simplifying
y = (x + 1) * 2(x2 + 2x)

Reorder the terms:
y = (1 + x) * 2(x2 + 2x)

Reorder the terms:
y = (1 + x) * 2(2x + x2)

Reorder the terms for easier multiplication:
y = 2(1 + x)(2x + x2)

Multiply (1 + x) * (2x + x2)
y = 2(1(2x + x2) + x(2x + x2))
y = 2((2x * 1 + x2 * 1) + x(2x + x2))
y = 2((2x + 1x2) + x(2x + x2))
y = 2(2x + 1x2 + (2x * x + x2 * x))
y = 2(2x + 1x2 + (2x2 + x3))

Combine like terms: 1x2 + 2x2 = 3x2
y = 2(2x + 3x2 + x3)
y = (2x * 2 + 3x2 * 2 + x3 * 2)
y = (4x + 6x2 + 2x3)

Solving
y = 4x + 6x2 + 2x3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 4x + 6x2 + 2x3

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